逻辑电路nand_通用逻辑门(NAND,NOR)
逻辑电路nand
NAND and NOR Gates are known as Universal Logic Gates, because we can realize any logic circuit or gate only by using NAND or NOR gates single-handedly.
NAND和NOR门被称为通用逻辑门 ,因为我们只能单手使用NAND或NOR门来实现任何逻辑电路或门。
Although the logic circuit of any complexity can be realized using three basic gates i.e., AND, OR, NOT Gates, but they can also be realized using only a single type of gate, that is why sometimes NAND and NOR gates are called "universal building blocks". Thus, AOI logic can be converted into NAND or NOR logic.
尽管可以使用三个基本门( 与门,或门,非门)来实现任何复杂度的逻辑电路,但也可以仅使用一种门来实现它们,因此有时将“ 与非 ” 门或“ 或非”门称为“通用建筑”块” 。 因此,AOI逻辑可以被转换成NAND或NOR逻辑 。
1)与非门 (1) NAND Gate)
NAND Gate is a combination of two gates. It is an AND Gate followed by a NOT Gate where the output of AND Gate is inverted using a NOT Gate to get the final output. The logic operation for the NAND gate can be written as Y= A.B
NAND门是两个门的组合。 它是一个“ 与”门,其后是一个“非”门,其中使用“ 非”门将 “与”门的输出反相以得到最终输出。 NAND门的逻辑运算可以写成Y = AB
Symbol and Truth Table for a two-input NAND Gate is:
两输入与非门的符号和真值表是:
2)或非门 (2) NOR Gate)
NOR Gate is also a combination of two gates namely, OR Gate followed by a NOT Gate where the output of OR Gate is inverted using a NOT Gate to get the final output. The logic operation of NOR Gate can be written as Y = A+B
或非门也是两个门的组合,即“或”门,其后是“非”门,其中使用“非”门将“或”门的输出反相以获得最终输出。 或非门的逻辑运算可以写成Y = A + B
Question 1: Realize the following gates by only using NAND Gates.
问题1:仅使用“与非”门来实现以下门。
AND
和
OR
要么
NOT
不
NOR
也不
XOR
异或
XNOR
异或
Answer:
回答:
AND Gate can be implemented using NAND Gate as:
可以使用“与非”门将“与”门实现为:
OR Gate can be implemented using NAND Gate as:
可以使用“与非”门来实现“或”门:
NOT Gate can be implemented using NAND Gate as:
NOT Gate可以使用NAND Gate实现为:
NOR Gate can be implemented using NAND Gate as:
可以使用“与非门”将“或非”门实现为:
XOR Gate can be implemented using NAND Gate as:
异或门可以使用与非门实现为:
XNOR Gate can be implemented using NAND Gate as:
可以使用NAND门将XNOR门实现为:
Question 2: Realize the following gates by only using NOR Gates.
问题2:仅使用“或非”门即可实现以下门。
AND
和
OR
要么
NOT
不
NOR
也不
XOR
异或
XNOR
异或
Answer:
回答:
AND Gate can be implemented using NOR Gate as:
可以使用“或非”门将“与”门实现为:
OR Gate can be implemented using NOR Gate as:
或门可以使用或非门来实现:
NOT Gate can be implemented using NOR Gate as:
NOT Gate可以使用NOR Gate来实现:
NAND Gate can be implemented using NOR Gate as:
NAND门可以使用NOR门实现为:
XOR Gate can be implemented using NOR Gate as:
异或门可以使用异或门来实现:
XNOR Gate can be implemented using NOR Gate as:
可以使用NOR Gate来实现XNOR Gate:
翻译自: https://www.includehelp.com/basics/universal-logic-gates-nand-nor.aspx
逻辑电路nand
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