1045. Customers Who Bought All Products

Table: Customer

±------------±--------+
| Column Name | Type |
±------------±--------+
| customer_id | int |
| product_key | int |
±------------±--------+
This table may contain duplicates rows.
customer_id is not NULL.
product_key is a foreign key (reference column) to Product table.

Table: Product

±------------±--------+
| Column Name | Type |
±------------±--------+
| product_key | int |
±------------±--------+
product_key is the primary key (column with unique values) for this table.

Write a solution to report the customer ids from the Customer table that bought all the products in the Product table.

Return the result table in any order.

The result format is in the following example.
 

Example 1:

Input:
Customer table:
±------------±------------+
| customer_id | product_key |
±------------±------------+
| 1 | 5 |
| 2 | 6 |
| 3 | 5 |
| 3 | 6 |
| 1 | 6 |
±------------±------------+
Product table:
±------------+
| product_key |
±------------+
| 5 |
| 6 |
±------------+
Output:
±------------+
| customer_id |
±------------+
| 1 |
| 3 |
±------------+
Explanation:
The customers who bought all the products (5 and 6) are customers with IDs 1 and 3.

From: LeetCode
Link: 1045. Customers Who Bought All Products

Solution:

Ideas:

• COUNT(DISTINCT c.product_key) counts how many different products each customer bought.
• (SELECT COUNT(*) FROM Product) counts how many products exist in total.
• If the two counts are equal, that customer bought all products.

Code:

# Write your MySQL query statement below
SELECT c.customer_id
FROM Customer c
GROUP BY c.customer_id
HAVING COUNT(DISTINCT c.product_key) = (SELECT COUNT(*) FROM Product);