例如现在有这样一个Json

String Value={"data":[{"school_name":"西北农林科技大学","school_id":"8"},{"school_name":"西北大学","school_id":"6"},{"school_name":"西北工业大学","school_id":"5"},{"school_name":"西北政法大学","school_id":"2"},{"school_name":"西安交通大学","school_id":"4"},{"school_name":"西安建筑科技大学","school_id":"10"},{"school_name":"西安电子科技大学","school_id":"3"},{"school_name":"西安邮电大学","school_id":"1"},{"school_name":"长安大学","school_id":"9"},{"school_name":"陕西师范大学","school_id":"7"},{"school_name":"陕西科技大学","school_id":"11"}],"msg":"列表获取成功","status":0}

用2个数组接收school_name和school_id

首先         

             public   String[] schoolID; 
             public  String[] schoolName;

             JSONObject  jsonObj_school；//用来接收解析的JSON字符串

             JSONArray  jsonArr_school ；//用来接收JSON对象里的数组

        try{
              jsonObj_school = new JSONObject ( Value ); //解析JSON字符串
              jsonArr_school  =jsonObj_school.getJSONArray("data");//接收JSON对象里的数组
              int jsonSize_school = jsonArr_school.length();.//获取数组长度
              schoolID = new String[ jsonSize_school ];//初始化数组
              schoolName = new String[ jsonSize_school];//初始化数组

          for(int i = 0; i < jsonSize_school; i++ )//通过循环取出数组里的值
              {
              JSONObject jsonTemp = (JSONObject)jsonArr_school.getJSONObject(i);
              schoolID[i] = jsonTemp.getString("school_id");
              schoolName[i] = jsonTemp.getString("school_name");
              }

           }catch(Exception e){

                    e.printStackTrace();
            }

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