本文翻译自：How do I concatenate strings and variables in PowerShell?

Suppose I have the following snippet: 假设我有以下代码段：

$assoc = New-Object psobject -Property @{
    Id = 42
    Name = "Slim Shady"
    Owner = "Eminem"
}

Write-host $assoc.Id + "  -  "  + $assoc.Name + "  -  " + $assoc.Owner

I'd expect this snippet to show: 我希望这个代码片段显示出来：

42 - Slim Shady - Eminem

But instead it shows: 但是它显示：

42 + - + Slim Shady + - + Eminem

Which makes me think the + operator isn't appropriate for concatenating strings and variables. 这使我认为+运算符不适用于连接字符串和变量。

How should you approach this with PowerShell? 如何使用PowerShell处理此问题？

#1楼

参考：https://stackoom.com/question/11Pgj/如何在PowerShell中连接字符串和变量

#2楼

您需要将表达式放在括号中，以防止将它们视为与cmdlet不同的参数：

Write-host ($assoc.Id + "  -  "  + $assoc.Name + "  -  " + $assoc.Owner)

#3楼

Write-Host "$($assoc.Id) - $($assoc.Name) - $($assoc.Owner)"

请参阅Windows PowerShell语言规范版本3.0 ，p34，子表达式扩展。

#4楼

One way is: 一种方法是：

Write-host "$($assoc.Id)  -  $($assoc.Name)  -  $($assoc.Owner)"

Another one is: 另一个是：

Write-host  ("{0}  -  {1}  -  {2}" -f $assoc.Id,$assoc.Name,$assoc.Owner )

Or just (but I don't like it ;) ): 或者只是（但我不喜欢它；））：

Write-host $assoc.Id  "  -  "   $assoc.Name  "  -  "  $assoc.Owner

#5楼

Try wrapping whatever you want to print out in parenthesis: 尝试用括号将要打印的内容包装起来：

Write-host ($assoc.Id + "  -  "  + $assoc.Name + "  -  " + $assoc.Owner)

Your code is being interpreted as many parameters being passed to Write-Host . 您的代码被解释为将许多参数传递给Write-Host 。 Wrapping it up inside parenthesis will concatenate the values and then pass the resulting value as a single parameter. 将其包装在括号内将串联这些值，然后将结果值作为单个参数传递。

#6楼

这是另一种替代方法：

Write-host (" {0}  -  {1}  -  {2}" -f $assoc.Id, $assoc.Name, $assoc.Owner)