golang的json的时间格式化解决方案

1.通过数据查询的时候指定号格式，这样就不要再转格式了
2.通过time.Time类型穿件别名，然后为这个别名类实现MarshalJSON方法。

以下来自golang的原来注释

If an encountered value implements the Marshaler interface
// and is not a nil pointer, Marshal calls its MarshalJSON method
// to produce JSON. If no MarshalJSON method is present but the
// value implements encoding.TextMarshaler instead, Marshal calls
// its MarshalText method.

// jsontest project main.go
package main

import (
    "encoding/json"
    "fmt"
    "time"
)

type jsonTime time.Time

//实现它的json序列化方法
func (this jsonTime) MarshalJSON() ([]byte, error) {
    var stamp = fmt.Sprintf("\"%s\"", time.Time(this).Format("2006-01-02 15:04:05"))
    return []byte(stamp), nil
}

type Test struct {
    Date  jsonTime `json:"date"`
    Name  string   `json:"name"`
    State bool     `json:"state"`
}

func main() {
    var t = Test{}
    t.Date = jsonTime(time.Now())
    t.Name = "Hello World"
    t.State = true
    body, _ := json.Marshal(t)
    fmt.Println(string(body))
}

输出结果:

{
    "date":"2016-11-04 13:42:24",
    "name":"Hello World",
    "state":true
}