TensorFlow提供两种类型的拼接:

tf.concat(values, axis, name='concat'):按照指定的已经存在的轴进行拼接
tf.stack(values, axis=0, name='stack'):按照指定的新建的轴进行拼接
t1 = [[1, 2, 3], [4, 5, 6]]
t2 = [[7, 8, 9], [10, 11, 12]]
tf.concat([t1, t2], 0) ==> [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
tf.concat([t1, t2], 1) ==> [[1, 2, 3, 7, 8, 9], [4, 5, 6, 10, 11, 12]]
tf.stack([t1, t2], 0)  ==> [[[1, 2, 3], [4, 5, 6]], [[7, 8, 9], [10, 11, 12]]]
tf.stack([t1, t2], 1)  ==> [[[1, 2, 3], [7, 8, 9]], [[4, 5, 6], [10, 11, 12]]]
tf.stack([t1, t2], 2)  ==> [[[1, 7], [2, 8], [3, 9]], [[4, 10], [5, 11], [6, 12]]]
t1 = [[1, 2, 3], [4, 5, 6]]
t2 = [[7, 8, 9], [10, 11, 12]]
tf.concat([t1, t2], 0)  # [2,3] + [2,3] ==> [4, 3]
tf.concat([t1, t2], 1)  # [2,3] + [2,3] ==> [2, 6]
tf.stack([t1, t2], 0)   # [2,3] + [2,3] ==> [2*,2,3]
tf.stack([t1, t2], 1)   # [2,3] + [2,3] ==> [2,2*,3]
tf.stack([t1, t2], 2)   # [2,3] + [2,3] ==> [2,3,2*]
GitHub 加速计划 / te / tensorflow
184.55 K
74.12 K
下载
一个面向所有人的开源机器学习框架
最近提交(Master分支:2 个月前 )
a49e66f2 PiperOrigin-RevId: 663726708 2 个月前
91dac11a This test overrides disabled_backends, dropping the default value in the process. PiperOrigin-RevId: 663711155 2 个月前
Logo

旨在为数千万中国开发者提供一个无缝且高效的云端环境,以支持学习、使用和贡献开源项目。

更多推荐