正如@alecxe所指出的，您需要将从文件中获得的列表数组划分为包含7个或更少元素的值组。然后，您可以获取一个包含任意7个标题的列表，并将它们用作键来创建最终列表中每个json对象的字典。try:

from itertools import izip

except ImportError: # Python 3

izip = zip

try:

xrange

except NameError: # Python 3

xrange = range

def grouper(n, sequence):

for i in xrange(0, len(sequence), n):

yield sequence[i:i+n]

data = [['String 1'],['String 2'],['String 3'],['String 4'],['String 5'],

['String 6'],['String 7'],['String 8'],['String 9'],['String 9'],

['String 10']]

titles = ['title1', 'title2', 'title3', 'title4', 'title5', 'title6', 'title7']

values = [e[0] for g in grouper(7, data) for e in g]

keys = (titles[i%7] for i in xrange(len(values)))

objs = [dict(g) for g in grouper(7, list(izip(keys, values)))]

print(objs)

输出：[{'title1': 'String 1', 'title2': 'String 2', 'title3': 'String 3',

'title4': 'String 4', 'title5': 'String 5', 'title6': 'String 6',

'title7': 'String 7'}, {'title1': 'String 8', 'title2': 'String 9',

'title3': 'String 9', 'title4': 'String 10'}]