<T> Future<T> submit(Callable<T> task);

   <T> Future<T> submit(Runnable task, T result);

    Future<?> submit(Runnable task);


三个重载方法,第一个很好理解,传入callable,本身call函数就有一个返回值,可以正常取得。

第二个第三个就不清楚怎么可以取到返回值了,因为Runnable本身的run方法也没有返回值,为什么要这么做,如果没有返回值,直接用execute方法就好,为什么还要下面这几个submit方法呢。

package thread.pool;

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;

public class PoolTest {
    public static void main(String[] args) {
		ExecutorService executor = Executors.newFixedThreadPool(3);
		Future<?> submit = executor.submit(new Runnable(){

			@Override
			public void run() {
				System.out.println("hehe");				
			}			
		});
		try {
			System.out.println(submit.get());
		} catch (Exception e) {
			
		}
	}
}
输出:
hehe
null
submit提交的任务,正常执行,返回的是null,不清楚有什么意义

package thread.pool;

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;

public class PoolTest {
    public static void main(String[] args) {
		ExecutorService executor = Executors.newFixedThreadPool(3);
		Future<?> submit = executor.submit(new Runnable(){

			@Override
			public void run() {
				System.out.println("how");
				throw new RuntimeException("hehe");				
			}			
		});
		try {
			Object obj = submit.get();
			System.out.println(obj);
		} catch (Exception e) {
			
			System.out.println(e.getMessage() + "  exception");
			
		}
	}
}

how
java.lang.RuntimeException: hehe  exception
任务里抛出异常,返回值可以get到该异常,继续抛出,不懂。

package thread.pool;

import java.util.concurrent.Callable;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
import java.util.concurrent.FutureTask;

public class PoolTest {
    public static void main(String[] args) {
		ExecutorService executor = Executors.newFixedThreadPool(3);
		FutureTask<String> ft = new FutureTask<String>(new Callable<String>(){

			@Override
			public String call() throws Exception {
				
				return "hehe";
			}
			
		});
		Future<?> submit = executor.submit(ft);
		try {
			;
			System.out.println("1" + submit.get());
			System.out.println("2" + ft.get());
		} catch (Exception e) {
			
			System.out.println(e.getMessage() + "  exception");
			
		}
		executor.shutdown();
	}
   
}
输出:

1null
2hehe

package thread.pool;

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;

public class PoolTest {
	static String aa = "he";
    public static void main(String[] args) {
		ExecutorService executor = Executors.newFixedThreadPool(3);
		
		Future<?> submit = executor.submit(new Runnable(){

			@Override
			public void run() {
				System.out.println("how");
				aa = aa + "he";			
			}			
		},aa);
		try {
			System.out.println(submit.get());
		} catch (Exception e) {
			
		}
	}
}
输出:

how
he

结论:终于还是没搞懂,这两个函数的使用场景是什么。

觉得应该是:

execute提交runnable执行就好

submit提交callable,取得返回值就好

为什么要submit提交runnable呢








GitHub 加速计划 / th / ThreadPool
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A simple C++11 Thread Pool implementation
最近提交(Master分支:2 个月前 )
9a42ec13 - 9 年前
fcc91415 - 9 年前
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