C#中使用JsonConvert解析JSON
json
适用于现代 C++ 的 JSON。
项目地址:https://gitcode.com/gh_mirrors/js/json
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1、首先下载 Newtonsoft.Json.dll 文件,然后添加Newtonsoft.Json的引用
2、using Newtonsoft.Json
3、JSON序列化
string JsonStr= JsonConvert.SerializeObject(Entity);
public class RecordResult
{
[JsonProperty("status")]
public int Status { get; set; }
[JsonProperty("error")]
public int Error { get; set; }
}
RecordResult result = new RecordResult();
result.Status = 1;
result.Error = "Error message";
string jsonStr = JsonConvert.SerializeObject(result);
4、JSON反序列化
Class model = JsonConvert.DeserializeObject<Class>(jsonstr);
var result = (RecordResult)JsonConvert.DeserializeObject(jsonstring, typeof(RecordResult))
//或者
var result = JsonConvert.DeserializeObject<RecordResult>(jsonstring)
原文链接:https://www.cnblogs.com/kevin860/p/11113112.html
GitHub 加速计划 / js / json
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适用于现代 C++ 的 JSON。
最近提交(Master分支:3 个月前 )
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* :page_facing_up: bump the copyright years
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* :page_facing_up: bump the copyright years
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* add a ci step for Json_Diagnostic_Positions
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* fix ci_test_diagnostics
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