一：介绍

JsonUtility是Unity自带的一个类，简单，效率高，不依赖第三方的库，但是对于一些复杂的要求还是需要导入第三方库去实现

二：使用

{
"personList":
[
{
"Name":"liu",
"Age":1
},
{
"Name":"Yin",
"Age":2
}
]
}

using System.Collections.Generic;
using UnityEngine;
using System;

public class ParseJson : MonoBehaviour
{
    private void Awake()
    {
        TextAsset json_txt = Resources.Load<TextAsset>("TestJson");
        PersonRoot data = JsonUtility.FromJson<PersonRoot>(json_txt.text);

        foreach (var temp in data.personList)
        {
            Debug.Log(String.Format("姓名:{0}==年龄{1}", temp.Name, temp.Age));
        }
    }
}

[Serializable]
public class PersonData
{
    public string Name;

    public int Age;
}

[Serializable]
public class PersonRoot
{
    public List<PersonData> personList;
}

三：踩坑点

——JsonUtility.FromJson方法只能接受一个JSON对象，否则会报错“JSON must represent an object type”
例如有多个对象时必须将多个对象定义为一个JSON对象

——无法直接解析枚举类型
JsonUtility无法直接解析枚举类型，需要在JSON文件中定义与枚举类型相对应的字符串类型，之后在实体类中实现ISerializationCallbackReceiver接口将字符串转换为枚举类型

using System.Collections.Generic;
using UnityEngine;
using System;

public class ParseJson : MonoBehaviour
{
    private void Awake()
    {
        TextAsset json_txt = Resources.Load<TextAsset>("TestJson");
        PersonRoot data = JsonUtility.FromJson<PersonRoot>(json_txt.text);

        foreach (var temp in data.personList)
        {
            Debug.Log(String.Format("姓名:{0}==年龄{1}==类型{2}", temp.Name, temp.Age, temp.PersonType));
        }
    }
}

[Serializable]
public class PersonData : ISerializationCallbackReceiver
{
    public string Name;

    public int Age;

    public PersonType PersonType;
    public string PersonTypeStr;

    public void OnAfterDeserialize()
    {
        PersonType type = (PersonType)Enum.Parse(typeof(PersonType), PersonTypeStr);
        PersonType = type;
    }

    public void OnBeforeSerialize()
    {
        throw new NotImplementedException();
    }
}

[Serializable]
public class PersonRoot
{
    public List<PersonData> personList;
}

public enum PersonType
{
    Teacher,
    Student,
}