Unable to infer base url. This is common when using dynamic servlet registration or when the API is
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问题描述:
springboot集成swagger遇到的问题:
Unable to infer base url. This is common when using dynamic servlet registration or when the API is behind an API Gateway. The base url is the root of where all the swagger resources are served. For e.g. if the api is available at http://example.org/api/v2/api-docs then the base url is http://example.org/api/. Please enter the location manually:

解决办法:
方法一:springboot启动类上添加@EnableSwagger2注解
@SpringBootApplication
@EnableSwagger2
public class EduApplication {
public static void main(String[] args) {
SpringApplication.run(EduApplication.class,args);
}
}
方法二:写一个SwaggerConfig类,类上添加@EnableSwagger注解,在springboot启动类上添加@ComponentScan(basePackages = “com.wzy”) 指明扫描包的路径
package com.wzy.servicebase;
import com.google.common.base.Predicates;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import springfox.documentation.builders.ApiInfoBuilder;
import springfox.documentation.builders.PathSelectors;
import springfox.documentation.service.ApiInfo;
import springfox.documentation.service.Contact;
import springfox.documentation.spi.DocumentationType;
import springfox.documentation.spring.web.plugins.Docket;
import springfox.documentation.swagger2.annotations.EnableSwagger2;
/**
* @author wzy
* @create 2021-11-12 15:10
* @description
*/
@Configuration//配置类
@EnableSwagger2 //swagger注解
public class SwaggerConfig {
@Bean
public Docket webApiConfig(){
return new Docket(DocumentationType.SWAGGER_2)
.groupName("webApi")
.apiInfo(webApiInfo())
.select()
.paths(Predicates.not(PathSelectors.regex("/admin/.*")))
.paths(Predicates.not(PathSelectors.regex("/error.*")))
.build();
}
private ApiInfo webApiInfo(){
return new ApiInfoBuilder()
.title("网站-课程中心API文档")
.description("本文档描述了课程中心微服务接口定义")
.version("1.0")
.contact(new Contact("java", "http://atguigu.com", "1123@qq.com"))
.build();
}
}
@SpringBootApplication
@ComponentScan(basePackages = "com.wzy")
public class EduApplication {
public static void main(String[] args) {
SpringApplication.run(EduApplication.class,args);
}
}
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