Every derived table must have its own alias(sql语句错误解决方法)
·
1. 在做多表查询,或者查询的时候产生新的表的时候会出现这个错误:Every derived table must have its own alias(每一个派生出来的表都必须有一个自己的别名)。
eg:
delete from stock
where (org_id,material_id,state)
in (SELECT * from
(select org_id,material_id, state from stock WHERE state = 1 group by org_id,material_id,state having count(*) > 1)
)
当执行这条sql语句的时候就会出现Every derived table must have its own alias;
2. 这条sql:
(select org_id,material_id, state from stock WHERE state = 1 group by org_id,material_id,state having count(*) > 1)
就会产生一张新的表,和前面的表stock联合查询,但是mysql要求每一个派生出来的表都必须有一个自己的别名,那我给派生表加上别名即可;
eg:修改后的sql,直接在新生产的表中加入 他的别命名就行(“as a”或者“a”),“a”为新表的别名
delete from stock
where (org_id,material_id,state) in
(SELECT * from (select org_id,material_id, state
from stock WHERE state = 1 group by org_id,material_id,state having count(*) > 1) as a )
这样就解决了问题;
AtomGit 是由开放原子开源基金会联合 CSDN 等生态伙伴共同推出的新一代开源与人工智能协作平台。平台坚持“开放、中立、公益”的理念,把代码托管、模型共享、数据集托管、智能体开发体验和算力服务整合在一起,为开发者提供从开发、训练到部署的一站式体验。
更多推荐



所有评论(0)